![Δμ GS O values at different P O2 , P H2O , and P H2 conditions at 850 °C. | Download Scientific Diagram Δμ GS O values at different P O2 , P H2O , and P H2 conditions at 850 °C. | Download Scientific Diagram](https://www.researchgate.net/publication/368919847/figure/tbl1/AS:11431281123733424@1677787228040/Dm-GS-O-values-at-different-P-O2-P-H2O-and-P-H2-conditions-at-850-C.png)
Δμ GS O values at different P O2 , P H2O , and P H2 conditions at 850 °C. | Download Scientific Diagram
![Lập PTHH của các phản ứng sau: 1) P + O2 P2O5 1) SO3 + H2O ----> H2 SO4 3) KMNO4 ----> KMNO4 MnO2 + O2 4) H2 SO4 + KOH ----> K2 SO4 H2O 5) FeClh + Ch --> F Lập PTHH của các phản ứng sau: 1) P + O2 P2O5 1) SO3 + H2O ----> H2 SO4 3) KMNO4 ----> KMNO4 MnO2 + O2 4) H2 SO4 + KOH ----> K2 SO4 H2O 5) FeClh + Ch --> F](https://img.hoidap247.com/picture/question/20211206/large_1638755670315.jpg)
Lập PTHH của các phản ứng sau: 1) P + O2 P2O5 1) SO3 + H2O ----> H2 SO4 3) KMNO4 ----> KMNO4 MnO2 + O2 4) H2 SO4 + KOH ----> K2 SO4 H2O 5) FeClh + Ch --> F
![SOLVED: Theorem 3.4.1. If the random variable X N(p,o2), 02 > 0, then the random variable V = (X p)?/o2 is x2(1). Proof: Because V = W2 where W = (X - SOLVED: Theorem 3.4.1. If the random variable X N(p,o2), 02 > 0, then the random variable V = (X p)?/o2 is x2(1). Proof: Because V = W2 where W = (X -](https://cdn.numerade.com/ask_images/71f3a26658ab4f459d090b296e9ae079.jpg)